Question
The equations in this sytem were added to solve for x. What is the value of x?
Negative 2 x + y = 8. 5 x minus y = negative 5. 3 x = 3.
x = negative 3
x = negative 1
x = 1
x = 3
Negative 2 x + y = 8. 5 x minus y = negative 5. 3 x = 3.
x = negative 3
x = negative 1
x = 1
x = 3
Answers
Answered by
GPT-4o mini
To solve for \( x \) in the given system of equations, we should isolate it from the equations provided. The equations you provided are:
1. \(-2x + y = 8\)
2. \(5x - y = -5\)
3. \(3x = 3\)
Let’s start by solving the simplest equation, which is \(3x = 3\):
\[
3x = 3
\]
Dividing both sides by 3 gives:
\[
x = 1
\]
Now, we can check if this value is consistent with the other equations.
Substituting \( x = 1 \) into the first equation:
\[
-2(1) + y = 8
\]
\[
-2 + y = 8
\]
\[
y = 8 + 2 = 10
\]
Now substituting \( x = 1 \) and \( y = 10 \) into the second equation:
\[
5(1) - 10 = -5
\]
\[
5 - 10 = -5
\]
\[
-5 = -5 \quad \text{(This is true)}
\]
Since both the first and second equations are satisfied with \( x = 1 \) and \( y = 10 \), we conclude that:
\[
\boxed{1}
\]
Thus, the value of \( x \) is \( 1 \).
1. \(-2x + y = 8\)
2. \(5x - y = -5\)
3. \(3x = 3\)
Let’s start by solving the simplest equation, which is \(3x = 3\):
\[
3x = 3
\]
Dividing both sides by 3 gives:
\[
x = 1
\]
Now, we can check if this value is consistent with the other equations.
Substituting \( x = 1 \) into the first equation:
\[
-2(1) + y = 8
\]
\[
-2 + y = 8
\]
\[
y = 8 + 2 = 10
\]
Now substituting \( x = 1 \) and \( y = 10 \) into the second equation:
\[
5(1) - 10 = -5
\]
\[
5 - 10 = -5
\]
\[
-5 = -5 \quad \text{(This is true)}
\]
Since both the first and second equations are satisfied with \( x = 1 \) and \( y = 10 \), we conclude that:
\[
\boxed{1}
\]
Thus, the value of \( x \) is \( 1 \).
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