The balanced chemical equation given is:
\[ \text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3 \]
Let's analyze the equation:
- On the products side, the amount of atoms can be calculated as follows:
- In \( 2\text{NH}_3 \):
- Each \( NH_3 \) molecule has 1 nitrogen (N) and 3 hydrogens (H).
- So for 2 \( NH_3 \) molecules, we have:
- Nitrogen: \( 2 \times 1 = 2 \)
- Hydrogen: \( 2 \times 3 = 6 \)
- Total atoms in products = \( 2 + 6 = 8 \) atoms.
- In \( 2\text{NH}_3 \):
Now let's check the reactants side:
- For the reactants:
- In \( \text{N}_2 \): There are 2 nitrogen atoms.
- In \( 3\text{H}_2 \): Each \( H_2 \) molecule has 2 hydrogen atoms, so for 3 \( H_2 \):
- Hydrogen: \( 3 \times 2 = 6 \)
- Total atoms in reactants = \( 2 + 6 = 8 \) atoms.
Therefore, if there are 8 atoms in the products, there will also be 8 atoms in the reactants.
The correct answer is 8.