Question

Look at the chemical reaction below:

N2 +3H2 → 2NH3

If this equation has 8 atoms in it's products, how many atoms will there be in the reactants?

Responses

2
2

7
7

10
10

8

Answer 1

The balanced chemical equation given is:

\[ \text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3 \]

Let's analyze the equation:

- On the **products** side, the amount of atoms can be calculated as follows:
- In \( 2\text{NH}_3 \):
- Each \( NH_3 \) molecule has 1 nitrogen (N) and 3 hydrogens (H).
- So for 2 \( NH_3 \) molecules, we have:
- Nitrogen: \( 2 \times 1 = 2 \)
- Hydrogen: \( 2 \times 3 = 6 \)
- Total atoms in products = \( 2 + 6 = 8 \) atoms.

Now let's check the **reactants** side:

- For the reactants:
- In \( \text{N}_2 \): There are 2 nitrogen atoms.
- In \( 3\text{H}_2 \): Each \( H_2 \) molecule has 2 hydrogen atoms, so for 3 \( H_2 \):
- Hydrogen: \( 3 \times 2 = 6 \)
- Total atoms in reactants = \( 2 + 6 = 8 \) atoms.

Therefore, if there are 8 atoms in the products, there will also be **8 atoms in the reactants**.

The correct answer is **8**.