In the chemical reaction \( \text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3 \), let's break down the number of atoms in both the reactants and products.
Reactants:
- For \( \text{N}_2 \): 2 nitrogen (N) atoms
- For \( 3\text{H}_2 \): \( 3 \times 2 = 6 \) hydrogen (H) atoms
Total atoms in reactants = \( 2 , (\text{N}) + 6 , (\text{H}) = 8 \) atoms.
Products:
- For \( 2\text{NH}_3 \): Each \( \text{NH}_3 \) contains 1 nitrogen atom and 3 hydrogen atoms. Therefore, for 2 \( \text{NH}_3 \):
- Nitrogen: \( 2 \times 1 = 2 \) nitrogen atoms
- Hydrogen: \( 2 \times 3 = 6 \) hydrogen atoms
Total atoms in products = \( 2 , (\text{N}) + 6 , (\text{H}) = 8 \) atoms.
Thus, the number of atoms in the products is 8.