are we looking at
(5p-5)/p * 5p^2/(8p-8)
of so, then ...
5(p-1)/p * 5p^2/[8(p-1]
= 25p/8, p ≠ 1
Multiply:
5p-5/p times 5p^2/8p-8
2 answers
use substitution to solve each system of equations. of the systerm does not have exactly one solution, state wheather it has no solution or infinitely many solutions y=2x=3 y=4x-1