Question

When iron ( Fe ) is placed in a copper sulfate ( CuSO4 ) solution, the blue solution slowly turns light green and the iron is coated with copper.This equation shows the transfer of electrons during the reaction.Cu2++Fe→Cu+Fe2+ Which best describes what happens during this oxidation-reduction reaction?(1 point)ResponsesCopper gives up one electron and iron accepts one electron.Copper gives up one electron and iron accepts one electron.Copper gives up two electrons and iron accepts two electrons.Copper gives up two electrons and iron accepts two electrons.Iron gives up one electron and copper accepts one electron.Iron gives up one electron and copper accepts one electron.Iron gives up two electrons and copper accepts two electrons.

Answer 1

In the oxidation-reduction reaction between iron (Fe) and copper sulfate (CuSO4), the copper ions (Cu²⁺) accept electrons from iron, and iron loses electrons in the process. The relevant equation is:

\[ \text{Cu}^{2+} + \text{Fe} \rightarrow \text{Cu} + \text{Fe}^{2+} \]

In this case:

• Copper (Cu²⁺) is reduced because it gains electrons to become solid copper (Cu).
• Iron (Fe) is oxidized because it loses electrons to become iron ions (Fe²⁺).

From the equation, iron (Fe) gives up two electrons while copper (Cu²⁺) accepts two electrons.

Thus, the best description of what happens during this oxidation-reduction reaction is:

Copper gives up two electrons and iron accepts two electrons.