Question
Mr. Edmonds gave his students an inequality and told them to write possible solutions.
3x + 2(4x + 2) less than 2(6x + 1)
What values would be incorrect student responses? Select TWO correct answers.
Group of answer choices
0
4
2
3
3x + 2(4x + 2) less than 2(6x + 1)
What values would be incorrect student responses? Select TWO correct answers.
Group of answer choices
0
4
2
3
Answers
Answered by
GPT-4o mini
Let's first solve the inequality to find the possible values for \(x\).
Starting from the inequality:
\[ 3x + 2(4x + 2) < 2(6x + 1) \]
First, expand both sides:
\[ 3x + 8x + 4 < 12x + 2 \]
Combine like terms on the left side:
\[ 11x + 4 < 12x + 2 \]
Now, isolate \(x\):
Subtract \(11x\) from both sides:
\[ 4 < x + 2 \]
Then, subtract \(2\) from both sides:
\[ 2 < x \]
This simplifies to:
\[ x > 2 \]
Now, this means any value of \(x\) that is greater than 2 is a correct solution to the inequality. Values less than or equal to 2 would be incorrect solutions.
Among the given options:
- **0** (incorrect, since \(0 < 2\))
- **4** (correct, since \(4 > 2\))
- **2** (incorrect, since \(2 < 2\) is not true)
- **3** (correct, since \(3 > 2\))
Thus, the two incorrect student responses are:
- **0**
- **2**
Starting from the inequality:
\[ 3x + 2(4x + 2) < 2(6x + 1) \]
First, expand both sides:
\[ 3x + 8x + 4 < 12x + 2 \]
Combine like terms on the left side:
\[ 11x + 4 < 12x + 2 \]
Now, isolate \(x\):
Subtract \(11x\) from both sides:
\[ 4 < x + 2 \]
Then, subtract \(2\) from both sides:
\[ 2 < x \]
This simplifies to:
\[ x > 2 \]
Now, this means any value of \(x\) that is greater than 2 is a correct solution to the inequality. Values less than or equal to 2 would be incorrect solutions.
Among the given options:
- **0** (incorrect, since \(0 < 2\))
- **4** (correct, since \(4 > 2\))
- **2** (incorrect, since \(2 < 2\) is not true)
- **3** (correct, since \(3 > 2\))
Thus, the two incorrect student responses are:
- **0**
- **2**
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