Question

A diagram of a closed circuit with a power source on the left labeled 6 V. There are 3 resistors in parallel, separate paths, connected to it labeled B 10 Ohms, C 20 Ohms and D 50 Ohms. The branch with the power source is labeled A. There are vectors in the clockwise direction across all three resistors and in the branch with the power source.
Perform calculations using the circuit illustrated. Round all the numerical answers to the tenths place.

The expected current at point A is

Answer 1

To calculate the expected current at point A in the closed circuit with a power source of 6 V and three resistors (B, C, and D) connected in parallel, we first need to find the equivalent resistance of the parallel resistors.

### Step 1: Calculate the Equivalent Resistance (R_eq)

For resistors in parallel, the formula for total or equivalent resistance \( R_{eq} \) is given by:

\[
\frac{1}{R_{eq}} = \frac{1}{R_B} + \frac{1}{R_C} + \frac{1}{R_D}
\]

Where:
- \( R_B = 10 \, \Omega \)
- \( R_C = 20 \, \Omega \)
- \( R_D = 50 \, \Omega \)

Now we can calculate:

\[
\frac{1}{R_{eq}} = \frac{1}{10} + \frac{1}{20} + \frac{1}{50}
\]

Calculating each term:

\[
\frac{1}{10} = 0.1, \quad \frac{1}{20} = 0.05, \quad \frac{1}{50} = 0.02
\]

Now summing these values:

\[
\frac{1}{R_{eq}} = 0.1 + 0.05 + 0.02 = 0.17
\]

Now we find \( R_{eq} \):

\[
R_{eq} = \frac{1}{0.17} \approx 5.882 \, \Omega
\]

### Step 2: Calculate the Current at Point A

Using Ohm's Law, the total current \( I \) flowing from the power source can be calculated using:

\[
I = \frac{V}{R_{eq}}
\]

Where:
- \( V = 6 \, V \)

Now substituting the values:

\[
I = \frac{6}{5.882} \approx 1.18 \, A
\]

### Conclusion

The expected current at point A is approximately:

\[
\boxed{1.2 \, A}
\]