Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Calculate the pH of a solution prepared by mixing 25.0 mL of 0.60 M HC2H3O2 and 15.0 mL of 0.60 M NaC2H3O2?Asked by Julie
Calculate the pH of a solution prepared by mixing 25.0 mL of 0.60 M HC2H3O2 and 15.0 mL of 0.60 M NaOH?
Answers
Answered by
DrBob222
duplicate post.
Answered by
Julie
One is using NaOH and the other NaC2H3O2, but will I still get the same pH for both?
Answered by
DrBob222
I apologize. I didn't see the difference at first glance. No, the answer is not the same.
The first one is a buffered solution and the pH = 4.52 but check my arithmetic.
The second one is 25 x 0.6 = 9 millimoles acetic acid.
Add 15 mL x 0.6 NaOH = 9 mmoles NaOH.
You will form 9 mmoles acetate ion and that will neutralize 9 mmoles of acetic acid leaving 15-9 = 6 mmoles acetic acid. Redo the HH equation and solve for pH.
The first one is a buffered solution and the pH = 4.52 but check my arithmetic.
The second one is 25 x 0.6 = 9 millimoles acetic acid.
Add 15 mL x 0.6 NaOH = 9 mmoles NaOH.
You will form 9 mmoles acetate ion and that will neutralize 9 mmoles of acetic acid leaving 15-9 = 6 mmoles acetic acid. Redo the HH equation and solve for pH.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.