To balance the reaction between methane (CH4) and oxygen (O2) that forms carbon dioxide (CO2) and water (H2O), we can follow these steps:
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Write the unbalanced equation: \[ \text{CH}_4 + \text{O}_2 \rightarrow \text{CO}_2 + \text{H}_2\text{O} \]
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Count the number of each type of atom on both sides of the equation:
- Left side: 1 C (from CH4), 4 H (from CH4), 2 O (from O2)
- Right side: 1 C (from CO2), 2 H (from H2O), 3 O (1 from CO2 and 2 from H2O)
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To balance the equation, we'll start with carbon and hydrogen:
- Carbon: 1 on both sides (already balanced).
- For hydrogen, we need 4 H on the right side, so we need to have 2 H2O molecules: \[ \text{CH}_4 + \text{O}_2 \rightarrow \text{CO}_2 + 2\text{H}_2\text{O} \]
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Now, the equation looks like: \[ \text{CH}_4 + \text{O}_2 \rightarrow \text{CO}_2 + 2\text{H}_2\text{O} \] At this point, there are:
- Left side: 1 C, 4 H (from CH4), 2 O
- Right side: 1 C, 4 H (from 2 H2O), and 3 O (1 from CO2 and 2 from 2 H2O)
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To balance the oxygen, you have 2 O on the left and 3 O on the right. To balance the oxygen, you need 2 O2 molecules: \[ \text{CH}_4 + 2\text{O}_2 \rightarrow \text{CO}_2 + 2\text{H}_2\text{O} \]
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Now we can check the count again:
- Left: 1 C, 4 H (from CH4), 4 O (from 2 O2)
- Right: 1 C, 4 H (from 2 H2O), 4 O (3 from products)
After balancing, the final balanced equation is: \[ \text{CH}_4 + 2\text{O}_2 \rightarrow \text{CO}_2 + 2\text{H}_2\text{O} \]
Conclusion: Two O2 molecules are necessary to complete the reaction. The correct response is two.