Asked by curtis

I need to know if I am anywhere in solving this problem:

Please tell me if this is correct.
The pH of a solution: 0.20 M CH3COOH and 0.10 M CH3COONa

pH=pKa+log{[CH3COONa]/[CH3COOH]}
pH= -log(1.8x10-5)+log{0.10/0.20}
pH= 4.74+log 0.50= 4.74-0.30= 4.44
Answered by DrBob222
You are SOOO right.
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