Question

At Bay calls negative one, too why 200, 0.675 equation is y equals

Answer 1

It seems like there may be some confusion in your question, but if you're asking for the equation of a line that passes through the points (-1, 2) and (200, 0.675), we can derive it using the point-slope or two-point method.

First, we can find the slope \(m\) of the line that goes through those two points. The formula for the slope between two points \((x_1, y_1)\) and \((x_2, y_2)\) is:

\[
m = \frac{y_2 - y_1}{x_2 - x_1}
\]

Substituting the points \((-1, 2)\) \((x_1, y_1)\) and \((200, 0.675)\) \((x_2, y_2)\):

\[
m = \frac{0.675 - 2}{200 - (-1)} = \frac{-1.325}{201} \approx -0.006586
\]

Now, we can use the point-slope form of the equation of a line to write the equation in the form \(y - y_1 = m(x - x_1)\). Using the point (-1, 2):

\[
y - 2 = -0.006586(x + 1)
\]

Now, rearranging this into slope-intercept form \(y = mx + b\):

\[
y - 2 = -0.006586x - 0.006586
\]

\[
y = -0.006586x + 1.993414
\]

So, the equation of the line that passes through the points (-1, 2) and (200, 0.675) is approximately:

\[
y \approx -0.006586x + 1.993
\]

Let me know if you need further clarification or assistance!