Question
Sue bought a chocolate bar and received change for $2 in 16 coins, all nickels and quarters, how many of each kind are given?
quantity value total
nickels
quarters
together
quantity value total
nickels
quarters
together
Answers
Answered by
GPT-4o mini
To solve the problem, we can set up a system of equations based on the information provided.
Let \( n \) be the number of nickels and \( q \) be the number of quarters. We have the following information:
1. The total number of coins is 16.
2. The total value of the coins is $2, which is equivalent to 200 cents.
From this information, we can formulate our equations:
1. \( n + q = 16 \) (Equation 1: total number of coins)
2. \( 5n + 25q = 200 \) (Equation 2: total value of the coins in cents)
Now, we can simplify Equation 2 by dividing all terms by 5:
\[ n + 5q = 40 \] (Equation 3)
Now, we can solve the system of equations using Equation 1 and Equation 3.
### Step 1: From Equation 1, express \( n \) in terms of \( q \):
\[ n = 16 - q \]
### Step 2: Substitute \( n \) into Equation 3:
\[ (16 - q) + 5q = 40 \]
### Step 3: Combine like terms:
\[ 16 + 4q = 40 \]
### Step 4: Solve for \( q \):
\[ 4q = 40 - 16 \]
\[ 4q = 24 \]
\[ q = 6 \]
### Step 5: Substitute back to find \( n \):
\[ n = 16 - q \]
\[ n = 16 - 6 \]
\[ n = 10 \]
### Conclusion:
Sue received **10 nickels** and **6 quarters**.
To summarize the values:
| | quantity | value each | total value |
|----------|----------|------------|-------------|
| Nickels | 10 | 5 | 50 |
| Quarters | 6 | 25 | 150 |
| **Together** | **16** | | **200** |
Thus, the solution confirms that Sue has 10 nickels and 6 quarters for a total value of $2.
Let \( n \) be the number of nickels and \( q \) be the number of quarters. We have the following information:
1. The total number of coins is 16.
2. The total value of the coins is $2, which is equivalent to 200 cents.
From this information, we can formulate our equations:
1. \( n + q = 16 \) (Equation 1: total number of coins)
2. \( 5n + 25q = 200 \) (Equation 2: total value of the coins in cents)
Now, we can simplify Equation 2 by dividing all terms by 5:
\[ n + 5q = 40 \] (Equation 3)
Now, we can solve the system of equations using Equation 1 and Equation 3.
### Step 1: From Equation 1, express \( n \) in terms of \( q \):
\[ n = 16 - q \]
### Step 2: Substitute \( n \) into Equation 3:
\[ (16 - q) + 5q = 40 \]
### Step 3: Combine like terms:
\[ 16 + 4q = 40 \]
### Step 4: Solve for \( q \):
\[ 4q = 40 - 16 \]
\[ 4q = 24 \]
\[ q = 6 \]
### Step 5: Substitute back to find \( n \):
\[ n = 16 - q \]
\[ n = 16 - 6 \]
\[ n = 10 \]
### Conclusion:
Sue received **10 nickels** and **6 quarters**.
To summarize the values:
| | quantity | value each | total value |
|----------|----------|------------|-------------|
| Nickels | 10 | 5 | 50 |
| Quarters | 6 | 25 | 150 |
| **Together** | **16** | | **200** |
Thus, the solution confirms that Sue has 10 nickels and 6 quarters for a total value of $2.
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