Asked by richard
Graph three periods of the function. (identify period and phase shift and intercepts)
y = f(x) = √3/2 sin(2x) - 1/2 cos(2x)
if you can't graph it can you at least get it into that simpler form which is graph able.
y = f(x) = √3/2 sin(2x) - 1/2 cos(2x)
if you can't graph it can you at least get it into that simpler form which is graph able.
Answers
Answered by
drwls
That can be rewritten
sin(pi/3)sin 2x - cos(pi/3)cos2x
= cos(2x + pi/3)= cos [2(x + pi/6)]
which is a cosine function with an amplitude of 1, a period of pi and a phase shift of -pi/6
sin(pi/3)sin 2x - cos(pi/3)cos2x
= cos(2x + pi/3)= cos [2(x + pi/6)]
which is a cosine function with an amplitude of 1, a period of pi and a phase shift of -pi/6
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