Function B

x 0 2 4 6
y 2.50 4.03 5.56 7.09

Function C
y = 1.3x + 1
which is greater?

3 answers

To compare Function B and Function C, we need to calculate the values of Function C at the same x-values as Function B (0, 2, 4, and 6).

Given Function C:

\[ y = 1.3x + 1 \]

Now we will calculate the corresponding y-values for each x:

  1. For \( x = 0 \): \[ y = 1.3(0) + 1 = 1 \]

  2. For \( x = 2 \): \[ y = 1.3(2) + 1 = 2.6 + 1 = 3.6 \]

  3. For \( x = 4 \): \[ y = 1.3(4) + 1 = 5.2 + 1 = 6.2 \]

  4. For \( x = 6 \): \[ y = 1.3(6) + 1 = 7.8 + 1 = 8.8 \]

Now we can compare the values of Functions B and C for each x:

| x | Function B (y) | Function C (y) | |---|----------------|----------------| | 0 | 2.50 | 1 | | 2 | 4.03 | 3.6 | | 4 | 5.56 | 6.2 | | 6 | 7.09 | 8.8 |

Now let's analyze:

  • At \( x = 0 \): Function B (2.50) is greater than Function C (1).
  • At \( x = 2 \): Function B (4.03) is greater than Function C (3.6).
  • At \( x = 4 \): Function C (6.2) is greater than Function B (5.56).
  • At \( x = 6 \): Function C (8.8) is greater than Function B (7.09).

In summary, Function B is greater than Function C at \( x = 0 \) and \( x = 2 \), while Function C is greater at \( x = 4 \) and \( x = 6 \). Thus, there is not a single function that is consistently greater across all points.

is the graph a function or not a function
x y
4 4
5 5
5 0
7 8
10 1

A relation is considered a function if each input (x-value) maps to exactly one output (y-value). In other words, for every x-value, there should be only one corresponding y-value.

Let's analyze the provided pairs:

  • \( (4, 4) \)
  • \( (5, 5) \)
  • \( (5, 0) \)
  • \( (7, 8) \)
  • \( (10, 1) \)

In this case, the x-value \( 5 \) corresponds to two different y-values: \( 5 \) and \( 0 \).

Since one input (x = 5) maps to two distinct outputs (y = 5 and y = 0), this relation is not a function.