Question

Janine took the advertising department from her company on a round trip to meet with a potential client. Including Sarah a total of 13 people took the trip, She was ablato purchase coach tickets for $390 and first class tickets for $950. She used her total budget for airfare for the trip, which was $8990. How many first class tickets did she buy? How many coach tickets did she buy?

Answer 1

Let's define the variables for the number of tickets:

- Let \( x \) be the number of first-class tickets bought.
- Let \( y \) be the number of coach tickets bought.

We know from the problem statement that:

1. The total number of people (tickets) is 13:
\[
x + y = 13
\]

2. The total cost for the tickets was $8,990:
\[
950x + 390y = 8990
\]

Now we can solve this system of equations.

First, let's solve the first equation for \( y \):
\[
y = 13 - x
\]

Next, we substitute this expression for \( y \) into the second equation:
\[
950x + 390(13 - x) = 8990
\]

Expanding the equation:
\[
950x + 5070 - 390x = 8990
\]

Combining like terms:
\[
(950 - 390)x + 5070 = 8990
\]
\[
560x + 5070 = 8990
\]

Subtracting 5070 from both sides:
\[
560x = 8990 - 5070
\]
\[
560x = 3920
\]

Dividing both sides by 560:
\[
x = \frac{3920}{560} = 7
\]

Now that we have \( x \), we can find \( y \):
\[
y = 13 - x = 13 - 7 = 6
\]

So, Janine bought:
- \( 7 \) first-class tickets
- \( 6 \) coach tickets

**Answer:**
First class tickets: 7; Coach tickets: 6.