To determine the average deviation for both tables, we first need to find the average distance from the mean for each dataset.
Table 1:
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Distance from Mean: 0, 4, 2, 1, 0, 1, 1, 1, 2
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Average Deviation Calculation: \[ \text{Average Deviation} = \frac{\sum \text{Distance from Mean}}{n} \] where \( n \) is the number of data points.
\[ \sum \text{Distance from Mean} = 0 + 4 + 2 + 1 + 0 + 1 + 1 + 1 + 2 = 12 \] \[ n = 9 \] \[ \text{Average Deviation} = \frac{12}{9} \approx 1.33 \]
Table 2:
- Distance from Mean: 2, 1, 3, 3, 1, 1, 1, 1, 2
- Average Deviation Calculation: \[ \sum \text{Distance from Mean} = 2 + 1 + 3 + 3 + 1 + 1 + 1 + 1 + 2 = 15 \] \[ n = 9 \] \[ \text{Average Deviation} = \frac{15}{9} \approx 1.67 \]
Conclusion:
- Average Deviation for Table 1: \( \approx 1.33 \)
- Average Deviation for Table 2: \( \approx 1.67 \)
Thus, the correct response is: The second table has a larger average deviation.