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Exponential Decay Quick Check 1 of 51 of 5 Items Question A local bakery opened with new equipment worth $80,000. Ten years lat...Question
Exponential Decay Quick Check
1 of 51 of 5 Items
Question
A local bakery opened with new equipment worth $80,000. Ten years later, the owners’ accountants told them that their equipment had depreciated at a rate of 6 percent per year. Which equation would you use to create a sequence modeling this situation?(1 point)
Responses
an=80,000(0.06)n−1
a subscript n baseline equals 80,000 left parenthesis 0.06 right parenthesis superscript n minus 1 baseline
an=80,000(0.94)n
a subscript n baseline equals 80,000 left parenthesis 0.94 right parenthesis superscript n baseline
an=80,000(0.06)n
a subscript n baseline equals 80,000 left parenthesis 0.06 right parenthesis superscript n baseline
an=80,000(0.94)n−1
a subscript n baseline equals 80,000 left parenthesis 0.94 right parenthesis superscript n minus 1 baseline
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Answered by
GPT-4o mini
To model the exponential decay of the bakery equipment's value over time, we need to consider that the equipment depreciates at a rate of 6% per year.
The value of the equipment after \( n \) years can be modeled with the formula:
\[ a_n = a_0 (1 - r)^n \]
where:
- \( a_0 \) is the initial value (in this case, $80,000),
- \( r \) is the rate of depreciation (0.06 for 6%),
- \( n \) is the number of years.
In this scenario, the decay factor becomes \( 1 - r = 1 - 0.06 = 0.94 \).
Thus, the equation modeling the situation will be:
\[ a_n = 80,000 (0.94)^n \]
So, the correct response to select is:
**an=80,000(0.94)n**
This indicates the value of the equipment after \( n \) years at a rate of depreciation of 6% per year.
The value of the equipment after \( n \) years can be modeled with the formula:
\[ a_n = a_0 (1 - r)^n \]
where:
- \( a_0 \) is the initial value (in this case, $80,000),
- \( r \) is the rate of depreciation (0.06 for 6%),
- \( n \) is the number of years.
In this scenario, the decay factor becomes \( 1 - r = 1 - 0.06 = 0.94 \).
Thus, the equation modeling the situation will be:
\[ a_n = 80,000 (0.94)^n \]
So, the correct response to select is:
**an=80,000(0.94)n**
This indicates the value of the equipment after \( n \) years at a rate of depreciation of 6% per year.
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