Ava wrote the expression 4−12−3

Question

to determine the slope of a line. Which table might represent Ava’s line?(1 point)
Responses

x y
4 3
2 1
x y 4 3 2 1

x y
3 1
2 4


x y 3 1 2 4

x y
4 3
2 1
x y 4 3 2 1

x y
3 4
-1 -2

Answer 1

To determine which table might represent Ava's line based on the expression she wrote (4 - 12 - 3), let's first simplify that expression:

4 - 12 - 3 = 4 - 15 = -11

This value (-11) does not represent a slope; instead, due to the nature of the choices with two points, we need to identify the slope between the given points.

The slope $m$ of a line between two points $(x_1,y_1)$ and $(x_2,y_2)$ can be calculated using the formula:

$$m=\frac{y_2-y_1}{x_2-x_1}$$

Now we can calculate the slopes for each of the provided tables:

1. Table 1:

   • Points (4, 3) and (2, 1)
   • Slope = $\frac{1-3}{2-4}=\frac{-2}{-2}=1$

2. Table 2:

   • Points (3, 1) and (2, 4)
   • Slope = $\frac{4-1}{2-3}=\frac{3}{-1}=-3$

3. Table 3:

   • (Same as Table 1: 4, 3) and (2, 1)
   • Slope = $\frac{1-3}{2-4}=\frac{-2}{-2}=1$

4. Table 4:

   • Points (3, 4) and (-1, -2)
   • Slope = $\frac{-2-4}{-1-3}=\frac{-6}{-4}=\frac{3}{2}$

Now, summarizing the slopes:

• Table 1: Slope = 1
• Table 2: Slope = -3
• Table 3: Slope = 1
• Table 4: Slope = $\frac{3}{2}$

Given that Ava's slope calculation led to an expression that simplifies to -11 (and we don't directly use it) but the possible slopes derived from combinations of points did not yield meaningful indicators toward her expression, if you're looking for a specific slope representation or a non-ambiguous slope from combinations:

• If you want to align values aiming to get a specific result, note that neither represented slope aligns with -11 and thus are intrinsic to potentially alternate functions.

Therefore, Tables represented with a slope appear correctly defined, but the differences seem evident towards their relationships without detailed pre-expressions thus ideally:

If you're seeking the values utilizable across those, utilize Table 2 where resulting combination yields oriented negative slope which contrasts distinctly differing from first 2 examples producing positive yielding.

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If any points needed are recalibrated for specific needs or suited asks again per table values inputs or derived outputs, let me know!

Answer 2

whats the answer

Answer 3

To determine which table represents a line with a slope that Ava might have calculated, we will calculate the slope for each of the tables presented.

Given the tables:

1. Table 1:

   • Points: (4, 3) and (2, 1)
   • Slope = $\frac{1-3}{2-4}=\frac{-2}{-2}=1$

2. Table 2:

   • Points: (3, 1) and (2, 4)
   • Slope = $\frac{4-1}{2-3}=\frac{3}{-1}=-3$

3. Table 3: (same as Table 1)

   • Points: (4, 3) and (2, 1)
   • Slope = $\frac{1-3}{2-4}=\frac{-2}{-2}=1$

4. Table 4:

   • Points: (3, 4) and (-1, -2)
   • Slope = $\frac{-2-4}{-1-3}=\frac{-6}{-4}=\frac{3}{2}$

Now, looking at the slopes calculated from each table:

• Table 1: Slope = 1
• Table 2: Slope = -3
• Table 3: Slope = 1 (same as Table 1)
• Table 4: Slope = $\frac{3}{2}$

Since none of these slopes directly relate to the earlier interpretation of Ava's simplified expression (which yielded -11 and not impactful in linear comparison), we can choose:

Table 2:

• Slope = -3

This table is the one that includes a negative slope, which might better fit variations of linear reductions determining contrastive descent behaviors.

Final Answer: Table 2 might represent Ava’s line.