Question

A scatter plot is shown. The equation y = 1.1x + 15.8 is a good line of fit for the data.
Use the equation for the trend line to determine an estimated value of y, to the nearest
tenth, when x = 170.
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Answer 1

U sure

Answer 2

To find the estimated value of \( y \) when \( x = 170 \), you can substitute \( x \) into the equation of the trend line \( y = 1.1x + 15.8 \).

Substituting \( x = 170 \):

\[
y = 1.1(170) + 15.8
\]

Now calculate \( 1.1 \times 170 \):

\[
1.1 \times 170 = 187
\]

Next, add 15.8 to this result:

\[
y = 187 + 15.8 = 202.8
\]

So, the estimated value of \( y \) when \( x = 170 \) is \( 202.8 \).

To the nearest tenth, the value is:

\[
\boxed{202.8}
\]

Answer 3

Let me double-check the calculations for you:

We have the equation of the trend line:

\[
y = 1.1x + 15.8
\]

Now, substituting \( x = 170 \):

\[
y = 1.1(170) + 15.8
\]

First, calculate \( 1.1 \times 170 \):

\[
1.1 \times 170 = 187
\]

Next, add 15.8:

\[
y = 187 + 15.8 = 202.8
\]

Thus, the calculated value of \( y \) when \( x = 170 \) is indeed \( 202.8 \).

So the answer remains:

\[
\boxed{202.8}
\]

If you’re looking for something else or if there’s another factor to consider, please let me know!