To find the centroid of triangle ABC, we can use the formula for the centroid (G) of a triangle given its vertices at \( A(x_1, y_1) \), \( B(x_2, y_2) \), and \( C(x_3, y_3) \).
The coordinates of the centroid G are given by:
\[ G\left( \frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3} \right) \]
Given the vertices of triangle ABC:
- \( A(-3, -3) \)
- \( B(0, 6) \)
- \( C(4, -3) \)
We can plug the coordinates of the vertices into the centroid formula.
- Calculate \( x \)-coordinate of G:
\[ x_G = \frac{-3 + 0 + 4}{3} = \frac{1}{3} \]
- Calculate \( y \)-coordinate of G:
\[ y_G = \frac{-3 + 6 - 3}{3} = \frac{0}{3} = 0 \]
Thus, the coordinates of the centroid \( G \) are:
\[ G\left( \frac{1}{3}, 0 \right) \]
The centroid \( G \) is at the point \( \left( \frac{1}{3}, 0 \right) \).
From the given options, the correct answer is:
d. \( \left(\frac{1}{3}, 0\right) \)
This confirms that the medians of triangle ABC meet at a single point, which is the centroid.