Question

Put in descending order
2.3 times 10^-10, 3.2 times 10^-10, 2.3 times 10^-12, 2.3 times 10^-8

Answer 1

To put the numbers in descending order, we can first express them in a common format. Here are the given numbers:

1. \(2.3 \times 10^{-10}\)
2. \(3.2 \times 10^{-10}\)
3. \(2.3 \times 10^{-12}\)
4. \(2.3 \times 10^{-8}\)

Now, since \(10^{-8}\), \(10^{-10}\), and \(10^{-12}\) are powers of ten, we can compare the coefficients directly while keeping in mind that as the exponent decreases, the value increases.

Arranging them from largest to smallest by considering the exponent:

1. \(2.3 \times 10^{-8}\) (largest value)
2. \(2.3 \times 10^{-10}\)
3. \(3.2 \times 10^{-10}\)
4. \(2.3 \times 10^{-12}\) (smallest value)

Now, we need to compare \(2.3 \times 10^{-10}\) and \(3.2 \times 10^{-10}\):
- \(3.2 \times 10^{-10}\) is larger than \(2.3 \times 10^{-10}\).

Thus, the final order from largest to smallest is:

1. \(2.3 \times 10^{-8}\)
2. \(3.2 \times 10^{-10}\)
3. \(2.3 \times 10^{-10}\)
4. \(2.3 \times 10^{-12}\)

So the descending order is:

- \(2.3 \times 10^{-8}\)
- \(3.2 \times 10^{-10}\)
- \(2.3 \times 10^{-10}\)
- \(2.3 \times 10^{-12}\)