What is the value of f(-6) when f(x)=x^2 + 8x + 10 ?

A. -6x - 38


B. -2

C. -4

D. -74

1 answer

To find the value of \( f(-6) \) for the function \( f(x) = x^2 + 8x + 10 \), we simply substitute \(-6\) into the function.

First, substitute -6 for x:

\[ f(-6) = (-6)^2 + 8(-6) + 10 \]

Calculate each term:

  1. \((-6)^2 = 36\)
  2. \(8 \cdot (-6) = -48\)

Now add these values together:

\[ f(-6) = 36 - 48 + 10 \]

Now calculate:

\[ f(-6) = 36 - 48 = -12 \] \[ f(-6) = -12 + 10 = -2 \]

Thus, the value of \( f(-6) \) is \(-2\). The correct answer is:

B. -2