Question

Subtract: \(\left(3b-2c\right)-\left(6c+2b\right)-\left(b+c\right)\). (1 point)

Answer 1

To subtract the expression \(\left(3b-2c\right)-\left(6c+2b\right)-\left(b+c\right)\), we can start by distributing the negative signs across the individual terms.

Here's how to break it down step by step:

1. Rewrite the expression:
\[
(3b - 2c) - (6c + 2b) - (b + c)
\]

2. Distribute the negative signs:
\[
3b - 2c - 6c - 2b - b - c
\]

3. Combine like terms. First, let's combine the \(b\) terms:
\[
3b - 2b - b = (3 - 2 - 1)b = 0b = 0
\]

4. Now, combine the \(c\) terms:
\[
-2c - 6c - c = (-2 - 6 - 1)c = -9c
\]

5. Putting it all together, we have:
\[
0 - 9c = -9c
\]

Thus, the final result of the subtraction is:
\[
\boxed{-9c}
\]