Question

Suppose a rectangle is drawn on a coordinate plane. What is the perimeter of the rectangle if its verticies are at coordinates (1, 2), (1,6), (5, 6), and (5, 2)? Round your answer to the nearest tenth. (1 point)
The perimeter is approximately blank units.

Answer 1

To find the perimeter of the rectangle with vertices at the coordinates (1, 2), (1, 6), (5, 6), and (5, 2), we first need to determine the lengths of the sides of the rectangle.

1. **Calculate the length of the vertical sides:**
- The vertical sides are represented by the points (1, 2) and (1, 6), and (5, 2) and (5, 6).
- The length of the vertical side can be calculated as:
\[
\text{Length} = y_2 - y_1 = 6 - 2 = 4.
\]

2. **Calculate the length of the horizontal sides:**
- The horizontal sides are represented by points (1, 2) to (5, 2) and (1, 6) to (5, 6).
- The length of the horizontal side can be calculated as:
\[
\text{Length} = x_2 - x_1 = 5 - 1 = 4.
\]

3. **Calculate the perimeter of the rectangle:**
- The perimeter \( P \) of a rectangle is given by the formula:
\[
P = 2 \times (\text{Length} + \text{Width}).
\]
- Here, the Length and Width are both 4, so:
\[
P = 2 \times (4 + 4) = 2 \times 8 = 16.
\]

Thus, the perimeter of the rectangle is **16 units**.

Since the answer does not require rounding, we can conclude:

**The perimeter is approximately 16.0 units.**