Question
Use inspection to solve the equation $x^{2}=\frac {36}{169}$ then select the correct solution set below. If there
are no real solutions , select"There are no real solutions." (1 point)
$\{ -\frac {6}{13}\} $
$\{ -\frac {6}{13},\frac {6}{13}\} $
There are no real solutions
$\{ \frac {6}{13}\} $
are no real solutions , select"There are no real solutions." (1 point)
$\{ -\frac {6}{13}\} $
$\{ -\frac {6}{13},\frac {6}{13}\} $
There are no real solutions
$\{ \frac {6}{13}\} $
Answers
Answered by
GPT-4o mini
To solve the equation \( x^2 = \frac{36}{169} \) using inspection, we will take the square root of both sides.
First, we recognize that taking the square root of both sides yields two potential solutions:
\[
x = \sqrt{\frac{36}{169}} \quad \text{or} \quad x = -\sqrt{\frac{36}{169}}.
\]
Calculating the square root on the right side, we have:
\[
\sqrt{\frac{36}{169}} = \frac{\sqrt{36}}{\sqrt{169}} = \frac{6}{13}.
\]
Thus, the two possible solutions for \( x \) are:
\[
x = \frac{6}{13} \quad \text{and} \quad x = -\frac{6}{13}.
\]
This gives us the complete solution set:
\[
\{ -\frac{6}{13}, \frac{6}{13} \}.
\]
Now, referring to the options provided, the correct solution set is:
\[
\{ -\frac{6}{13}, \frac{6}{13} \}.
\]
First, we recognize that taking the square root of both sides yields two potential solutions:
\[
x = \sqrt{\frac{36}{169}} \quad \text{or} \quad x = -\sqrt{\frac{36}{169}}.
\]
Calculating the square root on the right side, we have:
\[
\sqrt{\frac{36}{169}} = \frac{\sqrt{36}}{\sqrt{169}} = \frac{6}{13}.
\]
Thus, the two possible solutions for \( x \) are:
\[
x = \frac{6}{13} \quad \text{and} \quad x = -\frac{6}{13}.
\]
This gives us the complete solution set:
\[
\{ -\frac{6}{13}, \frac{6}{13} \}.
\]
Now, referring to the options provided, the correct solution set is:
\[
\{ -\frac{6}{13}, \frac{6}{13} \}.
\]
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