A net force of 0.7 N is applied on a body. What happens to the acceleration of the body in a second trial if half of the net force is applied?(1 point)

Responses

The acceleration remains the same.
The acceleration remains the same.

The acceleration is the square of its original value.
The acceleration is the square of its original value.

The acceleration is half of its original value.
The acceleration is half of its original value.

The acceleration is double its original value.

1 answer

According to Newton's second law of motion, the acceleration (a) of an object is directly proportional to the net force (F) applied on it and inversely proportional to its mass (m). The relationship can be expressed by the equation:

\[ a = \frac{F}{m} \]

In the first trial, if a net force of 0.7 N is applied, the acceleration will be:

\[ a_1 = \frac{0.7 , \text{N}}{m} \]

In the second trial, if half of the net force is applied (which would be 0.35 N), the acceleration becomes:

\[ a_2 = \frac{0.35 , \text{N}}{m} \]

Since \(0.35, \text{N}\) is half of \(0.7, \text{N}\), the new acceleration \(a_2\) will be half of the original acceleration \(a_1\).

Therefore, the correct response is:

The acceleration is half of its original value.