For which equation is the order of steps to first divide both sides by 6 and then to add 8 to both sides?(1 point)

Question

Responses

6x − 8 = 48
6
𝑥

−

8

=

48
6 x minus 8 equals 48

6(x − 8) = 48
6
(
𝑥

−

8
)

=

48
6 left parenthesis x minus 8 right parenthesis equals 48

6(x + 8) = 48
6
(
𝑥

+

8
)

=

48
6 left parenthesis x plus 8 right parenthesis equals 48

8(x − 6) = 48.............

Answer 1

To determine the equation for which the order of steps is to first divide both sides by 6, and then add 8 to both sides, let's analyze the given equations.

1. 6x - 8 = 48:

   • Divide by 6: this doesn't work because 6 is not a factor of both sides as it stands.

2. 6(x - 8) = 48:

   • Divide by 6: this leads to \(x - 8 = 8\).
   • Then, adding 8 gives \(x = 16\). This works.

3. 6(x + 8) = 48:

   • Divide by 6: this leads to \(x + 8 = 8\).
   • Adding 8 after dividing would not make sense here to isolate \(x\).

4. 8(x - 6) = 48:

   • Divide by 8: this leads to \(x - 6 = 6\).
   • Then, adding 6 would not match with the defined steps.

The only equation from the above options that aligns with the steps of first dividing by 6 and then adding 8 is:

6(x - 8) = 48.