Question
Anylayze this chart on the effect of Mass on Gravitational Force between two objects:
Question: What happens to the Gravitational Force if ONE of the object's Mass was CUT IN HALF, while the other remained the same?
a
The gravitational force is halved
b
The gravitational force is doubled
c
The gravitational force is quadrupled
d
The gravitational force is cut into one fourth
Question: What happens to the Gravitational Force if ONE of the object's Mass was CUT IN HALF, while the other remained the same?
a
The gravitational force is halved
b
The gravitational force is doubled
c
The gravitational force is quadrupled
d
The gravitational force is cut into one fourth
Answers
GPT-4o mini
The gravitational force \( F \) between two objects is described by Newton's law of universal gravitation, which states:
\[
F = G \frac{m_1 m_2}{r^2}
\]
Where:
- \( F \) is the gravitational force,
- \( G \) is the gravitational constant,
- \( m_1 \) and \( m_2 \) are the masses of the two objects,
- \( r \) is the distance between the centers of the two objects.
If we cut the mass of one of the objects (say \( m_1 \)) in half, the new mass \( m_1' \) will be:
\[
m_1' = \frac{m_1}{2}
\]
Assuming the other mass \( m_2 \) and the distance \( r \) remain constant, the new gravitational force \( F' \) can be expressed as:
\[
F' = G \frac{m_1' m_2}{r^2} = G \frac{\left(\frac{m_1}{2}\right) m_2}{r^2}
\]
Simplifying this, we have:
\[
F' = \frac{1}{2} \left(G \frac{m_1 m_2}{r^2}\right) = \frac{1}{2} F
\]
This shows that if one of the object's masses is cut in half, the gravitational force between the two objects is also cut in half.
Therefore, the correct answer is:
**a. The gravitational force is halved.**
\[
F = G \frac{m_1 m_2}{r^2}
\]
Where:
- \( F \) is the gravitational force,
- \( G \) is the gravitational constant,
- \( m_1 \) and \( m_2 \) are the masses of the two objects,
- \( r \) is the distance between the centers of the two objects.
If we cut the mass of one of the objects (say \( m_1 \)) in half, the new mass \( m_1' \) will be:
\[
m_1' = \frac{m_1}{2}
\]
Assuming the other mass \( m_2 \) and the distance \( r \) remain constant, the new gravitational force \( F' \) can be expressed as:
\[
F' = G \frac{m_1' m_2}{r^2} = G \frac{\left(\frac{m_1}{2}\right) m_2}{r^2}
\]
Simplifying this, we have:
\[
F' = \frac{1}{2} \left(G \frac{m_1 m_2}{r^2}\right) = \frac{1}{2} F
\]
This shows that if one of the object's masses is cut in half, the gravitational force between the two objects is also cut in half.
Therefore, the correct answer is:
**a. The gravitational force is halved.**
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