Question

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Find the value of xxx if A=3x, B=1x+6A=3x,\ B=1x+6A=3x, B=1x+6 and C=1x+10C=1x+10C=1x+10



x=x=x=

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Answer 1

To find the value of \( x \), let's first clarify the given expressions for the angles \( A \), \( B \), and \( C \):

1. \( A = 3x \)
2. \( B = 1x + 6 \)
3. \( C = 1x + 10 \)

Since angles in a triangle must sum to 180 degrees, we can set up the following equation:

\[
A + B + C = 180
\]

Substituting the expressions for \( A \), \( B \), and \( C \) into the equation:

\[
3x + (1x + 6) + (1x + 10) = 180
\]

Now combine like terms:

\[
3x + 1x + 6 + 1x + 10 = 180
\]

\[
5x + 16 = 180
\]

Next, isolate \( x \) by subtracting 16 from both sides:

\[
5x = 180 - 16
\]
\[
5x = 164
\]

Now, divide both sides by 5 to solve for \( x \):

\[
x = \frac{164}{5}
\]

Calculating the division gives:

\[
x = 32.8
\]

Thus, the value of \( x \) is

\[
\boxed{32.8}
\]