To determine which equation has a solution different from the rest, we can solve each equation for \( x \).
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Equation: \(-\frac{1}{7}x - \frac{3}{4} = \frac{1}{4}\)
To isolate \( x \): \[ -\frac{1}{7}x = \frac{1}{4} + \frac{3}{4} \] \[ -\frac{1}{7}x = 1 \] Multiply both sides by -7: \[ x = -7 \]
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Equation: \(\frac{1}{2}x - 3 = \frac{1}{2}\)
Rearranging: \[ \frac{1}{2}x = \frac{1}{2} + 3 \] \[ \frac{1}{2}x = \frac{1}{2} + \frac{6}{2} = \frac{7}{2} \] Multiply both sides by 2: \[ x = 7 \]
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Equation: \(-0.35x - 0.52 = 1.93\)
Rearranging: \[ -0.35x = 1.93 + 0.52 \] \[ -0.35x = 2.45 \] Multiply both sides by -1/0.35: \[ x = -\frac{2.45}{0.35} \approx -7 \]
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Equation: \(\frac{3}{4}x + 5 = -\frac{1}{4}\)
Rearranging: \[ \frac{3}{4}x = -\frac{1}{4} - 5 \] \[ \frac{3}{4}x = -\frac{1}{4} - \frac{20}{4} = -\frac{21}{4} \] Multiply both sides by \(\frac{4}{3}\): \[ x = -\frac{21}{3} = -7 \]
Summary of solutions:
- First equation: \( x = -7 \)
- Second equation: \( x = 7 \)
- Third equation: \( x \approx -7 \)
- Fourth equation: \( x = -7 \)
The second equation is the only one with a solution different from the others, which is \( x = 7 \).