A 0.150 kg particle moves along an x axis according to x(t) = -13.00 + 2.00t + 3.50t2 - 2.50t3, with x in meters and t in seconds. In unit-vector notation, what is the net force acting on the particle at t = 3.45 s?

Answer 1

Compute the acceleration, x"(t). It equals 7 - 15t m/s^2.

Compute its value at t = 3.34 s

Divide that by the mass for the acceleration.