Question

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Part 1
At​ noon, a tank contained 6 in. of water. After several​ hours, it contained 3 in. of water. What is the percent decrease of water in the​ tank?

Answer 1

To calculate the percent decrease in the amount of water in the tank, you can use the formula:

\[
\text{Percent Decrease} = \left( \frac{\text{Initial Amount} - \text{Final Amount}}{\text{Initial Amount}} \right) \times 100
\]

In this case, the initial amount of water is 6 inches and the final amount is 3 inches. Plugging in these values:

\[
\text{Percent Decrease} = \left( \frac{6 \, \text{in.} - 3 \, \text{in.}}{6 \, \text{in.}} \right) \times 100
\]

Calculating the difference:

\[
6 \, \text{in.} - 3 \, \text{in.} = 3 \, \text{in.}
\]

Now substitute this value back into the formula:

\[
\text{Percent Decrease} = \left( \frac{3 \, \text{in.}}{6 \, \text{in.}} \right) \times 100
\]

This simplifies to:

\[
\text{Percent Decrease} = \left( 0.5 \right) \times 100 = 50\%
\]

Thus, the percent decrease in the water in the tank is **50%**.