Question

A hockey player, initially gliding along the ice at a speed of 1 meter per second, accelerates at 2 meters per second squared for 3 seconds.



What is the player's final speed?

Answer options with 5 options
A.
3 meters per second

B.
5 meters per second

C.
6 meters per second

D.
7 meters per second

E.
9 meters per second

Answer 1

To determine the player's final speed, we can use the formula for final velocity under constant acceleration:

\[
v_f = v_i + a \cdot t
\]

Where:
- \( v_f \) is the final velocity.
- \( v_i \) is the initial velocity (1 m/s).
- \( a \) is the acceleration (2 m/s²).
- \( t \) is the time (3 seconds).

Plugging in the values:

\[
v_f = 1 \, \text{m/s} + (2 \, \text{m/s}^2 \cdot 3 \, \text{s})
\]

Calculating the acceleration part:

\[
2 \, \text{m/s}^2 \cdot 3 \, \text{s} = 6 \, \text{m/s}
\]

Now adding this to the initial velocity:

\[
v_f = 1 \, \text{m/s} + 6 \, \text{m/s} = 7 \, \text{m/s}
\]

Therefore, the player's final speed is **7 meters per second**, which corresponds to option **D**.