Question
The seed color of pea plants is governed by a single gene with two alleles: the yellow-seed allele is dominant, and the green-seed allele is recessive. Students crossed a heterozygous yellow pea plant with a homozygous green pea plant.
What would be the probability of having offspring pea plants with yellow, green, or yellow-green seeds? Move the correct probabilities to the boxes corresponding to the traits.
Response area with 3 blank spaces
Yellow Seeds Green Seeds Yellow-Green Seeds
Blank space 1 empty
Blank space 2 empty
Blank space 3 empty
Answer options with 5 options.
A.0%
B.25%
C.50%
D.75%
E.100%
What would be the probability of having offspring pea plants with yellow, green, or yellow-green seeds? Move the correct probabilities to the boxes corresponding to the traits.
Response area with 3 blank spaces
Yellow Seeds Green Seeds Yellow-Green Seeds
Blank space 1 empty
Blank space 2 empty
Blank space 3 empty
Answer options with 5 options.
A.0%
B.25%
C.50%
D.75%
E.100%
Answers
GPT-4o mini
To determine the probabilities of offspring seed colors, we first need to establish the genotypes of the parental plants being crossed.
1. **Heterozygous yellow pea plant**: This plant has one yellow seed allele (Y) and one green seed allele (y), so its genotype is **Yy**.
2. **Homozygous green pea plant**: This plant has two green seed alleles (y), so its genotype is **yy**.
Next, we can use a Punnett square to visualize the potential offspring from this cross.
| | Y | y |
|-------|----|----|
| **y** | Yy | yy |
| **y** | Yy | yy |
From the Punnett square, we can see the possible genotypes of the offspring:
- **Yy**: This genotype is for yellow seeds because the yellow allele is dominant. We have 2 instances of this genotype.
- **yy**: This genotype is for green seeds because it has the recessive alleles. We have 2 instances of this genotype.
Now, we can calculate the probabilities:
- Probability of Yellow Seeds (Yy): 2 out of 4 = 50%
- Probability of Green Seeds (yy): 2 out of 4 = 50%
- There are no yellow-green seeds in this cross, as yellow-green seeds would require a different combination of alleles.
Now we can fill in the response areas:
- Yellow Seeds: **50% (C)**
- Green Seeds: **50% (C)**
- Yellow-Green Seeds: **0% (A)**
So, the completed response area would look like this:
Response area
- Yellow Seeds: 50%
- Green Seeds: 50%
- Yellow-Green Seeds: 0%
The correct placement of probabilities would be:
- Blank space 1 (Yellow Seeds): 50%
- Blank space 2 (Green Seeds): 50%
- Blank space 3 (Yellow-Green Seeds): 0%
1. **Heterozygous yellow pea plant**: This plant has one yellow seed allele (Y) and one green seed allele (y), so its genotype is **Yy**.
2. **Homozygous green pea plant**: This plant has two green seed alleles (y), so its genotype is **yy**.
Next, we can use a Punnett square to visualize the potential offspring from this cross.
| | Y | y |
|-------|----|----|
| **y** | Yy | yy |
| **y** | Yy | yy |
From the Punnett square, we can see the possible genotypes of the offspring:
- **Yy**: This genotype is for yellow seeds because the yellow allele is dominant. We have 2 instances of this genotype.
- **yy**: This genotype is for green seeds because it has the recessive alleles. We have 2 instances of this genotype.
Now, we can calculate the probabilities:
- Probability of Yellow Seeds (Yy): 2 out of 4 = 50%
- Probability of Green Seeds (yy): 2 out of 4 = 50%
- There are no yellow-green seeds in this cross, as yellow-green seeds would require a different combination of alleles.
Now we can fill in the response areas:
- Yellow Seeds: **50% (C)**
- Green Seeds: **50% (C)**
- Yellow-Green Seeds: **0% (A)**
So, the completed response area would look like this:
Response area
- Yellow Seeds: 50%
- Green Seeds: 50%
- Yellow-Green Seeds: 0%
The correct placement of probabilities would be:
- Blank space 1 (Yellow Seeds): 50%
- Blank space 2 (Green Seeds): 50%
- Blank space 3 (Yellow-Green Seeds): 0%