To determine the number of solutions to the system of equations:
- \(2x + y = 6\)
- \(4x + 2y = 8\)
First, let's simplify the second equation. Notice that we can divide the entire equation by 2:
\[ 2x + y = 4 \]
Now, we have the following system of equations:
- \(2x + y = 6\)
- \(2x + y = 4\)
Next, we can compare these two equations. Both have the same left-hand side (\(2x + y\)), but their right-hand sides are different (6 and 4). This indicates that there is a contradiction; the same expression cannot equal two different values simultaneously.
Thus, the two equations represent parallel lines which do not intersect.
Therefore, the system has 0 solutions.
So the answer is 0.