Question
Question
The size of a hydrogen atom is about 1.2×10^−10
1.2
×
10
−
10
m across. The size of an oxygen atom is 0.000000000152 m across. What is the difference between the sizes of these atoms in scientific notation?(1 point)
Responses
3.2×10^−9
3.2
×
10
−
9
m
3.2 times 10 superscript negative 9 baseline m
3.2 ×10^−10
3.2
×
10
−
10
m
3.2 times 10 superscript negative 10 baseline m
2.72×10^−10
2.72
×
10
−
10
m
2.72 times 10 superscript negative 10 baseline m
3.2×10^−11
3.2
×
10
−
11
m
The size of a hydrogen atom is about 1.2×10^−10
1.2
×
10
−
10
m across. The size of an oxygen atom is 0.000000000152 m across. What is the difference between the sizes of these atoms in scientific notation?(1 point)
Responses
3.2×10^−9
3.2
×
10
−
9
m
3.2 times 10 superscript negative 9 baseline m
3.2 ×10^−10
3.2
×
10
−
10
m
3.2 times 10 superscript negative 10 baseline m
2.72×10^−10
2.72
×
10
−
10
m
2.72 times 10 superscript negative 10 baseline m
3.2×10^−11
3.2
×
10
−
11
m
Answers
GPT-4o mini
To find the difference between the sizes of the hydrogen atom and the oxygen atom, we first need to express both sizes in scientific notation.
1. The size of the hydrogen atom is given as \(1.2 \times 10^{-10}\) m.
2. The size of the oxygen atom is given as \(0.000000000152\) m, which can also be written in scientific notation as \(1.52 \times 10^{-10}\) m.
Now, we will calculate the difference:
\[
\text{Difference} = \text{Size of hydrogen atom} - \text{Size of oxygen atom}
\]
\[
\text{Difference} = (1.2 \times 10^{-10}) - (1.52 \times 10^{-10})
\]
To perform this subtraction, we can write it as:
\[
\text{Difference} = (1.2 - 1.52) \times 10^{-10}
\]
Calculating \(1.2 - 1.52\):
\[
1.2 - 1.52 = -0.32
\]
Thus, the difference becomes:
\[
\text{Difference} = -0.32 \times 10^{-10}
\]
To express this in proper scientific notation, we convert \(-0.32\) to \(-3.2 \times 10^{-1}\):
So, we have:
\[
\text{Difference} = -3.2 \times 10^{-1} \times 10^{-10} = -3.2 \times 10^{-11}
\]
Now, since the question asks for the difference and only considers size, we take the absolute value:
\[
3.2 \times 10^{-11} \text{ m}
\]
The correct response is:
**3.2 × 10^−11 m**
1. The size of the hydrogen atom is given as \(1.2 \times 10^{-10}\) m.
2. The size of the oxygen atom is given as \(0.000000000152\) m, which can also be written in scientific notation as \(1.52 \times 10^{-10}\) m.
Now, we will calculate the difference:
\[
\text{Difference} = \text{Size of hydrogen atom} - \text{Size of oxygen atom}
\]
\[
\text{Difference} = (1.2 \times 10^{-10}) - (1.52 \times 10^{-10})
\]
To perform this subtraction, we can write it as:
\[
\text{Difference} = (1.2 - 1.52) \times 10^{-10}
\]
Calculating \(1.2 - 1.52\):
\[
1.2 - 1.52 = -0.32
\]
Thus, the difference becomes:
\[
\text{Difference} = -0.32 \times 10^{-10}
\]
To express this in proper scientific notation, we convert \(-0.32\) to \(-3.2 \times 10^{-1}\):
So, we have:
\[
\text{Difference} = -3.2 \times 10^{-1} \times 10^{-10} = -3.2 \times 10^{-11}
\]
Now, since the question asks for the difference and only considers size, we take the absolute value:
\[
3.2 \times 10^{-11} \text{ m}
\]
The correct response is:
**3.2 × 10^−11 m**