To analyze the function \( y = x^2 - 8x \), let's determine the key points such as the vertex, x-intercepts, and y-intercept.
Vertex
The vertex of a parabola described by the equation \( y = ax^2 + bx + c \) can be found using the formula:
\[ x = -\frac{b}{2a} \]
In this case, \( a = 1 \) and \( b = -8 \):
\[ x = -\frac{-8}{2 \cdot 1} = \frac{8}{2} = 4 \]
To find the y-coordinate of the vertex, substitute \( x = 4 \) back into the function:
\[ y = (4)^2 - 8(4) = 16 - 32 = -16 \]
Thus, the vertex is at the point \( (4, -16) \).
X-Intercepts
The x-intercepts occur when \( y = 0 \):
\[ 0 = x^2 - 8x \]
Factoring gives:
\[ 0 = x(x - 8) \]
Setting each factor to zero yields:
\[ x = 0 \quad \text{or} \quad x = 8 \]
So, the x-intercepts are at \( (0, 0) \) and \( (8, 0) \).
Y-Intercept
The y-intercept occurs when \( x = 0 \):
\[ y = (0)^2 - 8(0) = 0 \]
Thus, the y-intercept is at \( (0, 0) \).
Summary of Key Points
- Vertex: \( (4, -16) \)
- X-Intercepts: \( (0, 0) \) and \( (8, 0) \)
- Y-Intercept: \( (0, 0) \)
Answer Selection
Based on the analysis:
- Vertex: \( (4, -16) \)
- X-Intercepts: \( (0, 0) \) and \( (8, 0) \)
- Y-Intercept: \( (0, 0) \)
From the provided responses, the closest match would be:
- Vertex: \( (4, -16) \)
- X-intercepts: \( (0, 0) \) and \( (8, 0) \)
- Y-intercept: \( (0, 0) \)
None of the options provided match this conclusion perfectly; however, the correct way to summarize is:
- Vertex: \( (4, -16) \)
- X-intercepts: \( (0, 0) \) and \( (8, 0) \)
- Y-intercept: \( (0, 0) \)