Asked by unknown 2.0
Rita puts $10,000 into each of two different assets. The first asset pays 10 percent interest and the second pays 5 percent. According to the rule of 70, what is the approximate difference in the value of the two assets after 14 years?
a.
$20,000
b.
$12,000
c.
$14,000
d.
$15,500
a.
$20,000
b.
$12,000
c.
$14,000
d.
$15,500
Answers
Answered by
GPT-4o mini
The Rule of 70 is a way to estimate the number of years it takes for an investment to double in value by dividing 70 by the annual interest rate.
1. **For the first asset (10% interest):**
\[
\text{Doubling Time} = \frac{70}{10} = 7 \text{ years}
\]
After 14 years (which is 2 doubling periods), the amount will double twice:
\[
\text{Value} = 10,000 \times 2 \times 2 = 40,000
\]
2. **For the second asset (5% interest):**
\[
\text{Doubling Time} = \frac{70}{5} = 14 \text{ years}
\]
After 14 years, the amount will double once:
\[
\text{Value} = 10,000 \times 2 = 20,000
\]
3. **Calculating the difference:**
\[
\text{Difference in Value} = \text{Value of First Asset} - \text{Value of Second Asset} = 40,000 - 20,000 = 20,000
\]
Thus, the approximate difference in the value of the two assets after 14 years is:
**a. $20,000**
1. **For the first asset (10% interest):**
\[
\text{Doubling Time} = \frac{70}{10} = 7 \text{ years}
\]
After 14 years (which is 2 doubling periods), the amount will double twice:
\[
\text{Value} = 10,000 \times 2 \times 2 = 40,000
\]
2. **For the second asset (5% interest):**
\[
\text{Doubling Time} = \frac{70}{5} = 14 \text{ years}
\]
After 14 years, the amount will double once:
\[
\text{Value} = 10,000 \times 2 = 20,000
\]
3. **Calculating the difference:**
\[
\text{Difference in Value} = \text{Value of First Asset} - \text{Value of Second Asset} = 40,000 - 20,000 = 20,000
\]
Thus, the approximate difference in the value of the two assets after 14 years is:
**a. $20,000**
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