Question
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A graph shows quadrant 1 with the x-axis and y-axis ranging from 0 to positive 9, 3,2 and 7,8 are highlighted.
Apply the Pythagorean Theorem to find the length between the two points. Round your answer to the nearest hundredth.
A graph shows quadrant 1 with the x-axis and y-axis ranging from 0 to positive 9, 3,2 and 7,8 are highlighted.
Apply the Pythagorean Theorem to find the length between the two points. Round your answer to the nearest hundredth.
Answers
Answered by
GPT-4o mini
To find the distance between the points (3, 2) and (7, 8) using the Pythagorean Theorem, we can use the distance formula, which is derived from the Pythagorean Theorem:
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Where:
- \((x_1, y_1)\) = (3, 2)
- \((x_2, y_2)\) = (7, 8)
Now, we can substitute the coordinates into the formula:
\[
d = \sqrt{(7 - 3)^2 + (8 - 2)^2}
\]
Calculating the differences:
\[
d = \sqrt{(4)^2 + (6)^2}
\]
Now squaring the differences:
\[
d = \sqrt{16 + 36}
\]
\[
d = \sqrt{52}
\]
Now we can simplify \(\sqrt{52}\):
\[
d = \sqrt{4 \cdot 13} = 2\sqrt{13}
\]
Using a calculator, we approximate \(\sqrt{13}\):
\[
\sqrt{13} \approx 3.60555
\]
Therefore:
\[
d \approx 2 \times 3.60555 \approx 7.2111
\]
Rounding to the nearest hundredth:
\[
d \approx 7.21
\]
Thus, the length between the two points is approximately **7.21**.
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
Where:
- \((x_1, y_1)\) = (3, 2)
- \((x_2, y_2)\) = (7, 8)
Now, we can substitute the coordinates into the formula:
\[
d = \sqrt{(7 - 3)^2 + (8 - 2)^2}
\]
Calculating the differences:
\[
d = \sqrt{(4)^2 + (6)^2}
\]
Now squaring the differences:
\[
d = \sqrt{16 + 36}
\]
\[
d = \sqrt{52}
\]
Now we can simplify \(\sqrt{52}\):
\[
d = \sqrt{4 \cdot 13} = 2\sqrt{13}
\]
Using a calculator, we approximate \(\sqrt{13}\):
\[
\sqrt{13} \approx 3.60555
\]
Therefore:
\[
d \approx 2 \times 3.60555 \approx 7.2111
\]
Rounding to the nearest hundredth:
\[
d \approx 7.21
\]
Thus, the length between the two points is approximately **7.21**.
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