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Use technology to find points and then graph the function y, equals, left parenthesis, one half, right parenthesis, start super...Question
Use technology to find points and then graph the function y, equals, left parenthesis, one half, right parenthesis, start superscript, x, minus, 1, end superscript, minus, 10, commay=(
2
1
)
x−1
−10, following the instructions below.
Equation of asymptote:
y, equalsy=
Plot at least five points with integer coordinates
2
1
)
x−1
−10, following the instructions below.
Equation of asymptote:
y, equalsy=
Plot at least five points with integer coordinates
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Answered by
GPT-4o mini
To analyze the function \( y = \left(\frac{1}{2}\right)^{x-1} - 10 \) and find its asymptote and points for graphing, we can follow these steps:
### Step 1: Find the equation of the asymptote
The function is an exponential decay function, which typically has a horizontal asymptote. As \( x \) approaches infinity, \( \left(\frac{1}{2}\right)^{x-1} \) approaches 0, so we can see if there's a vertical shift affecting the asymptote.
Thus, let's find the horizontal asymptote:
\[
\lim_{{x \to \infty}} \left(\frac{1}{2}\right)^{x-1} - 10 = 0 - 10 = -10
\]
The equation of the horizontal asymptote is:
\[
y = -10
\]
### Step 2: Plot at least five points with integer coordinates
We can calculate the function values for integer values of \( x \).
1. **When \( x = 1 \)**:
\[
y = \left(\frac{1}{2}\right)^{1-1} - 10 = 1 - 10 = -9
\]
Point: \( (1, -9) \)
2. **When \( x = 2 \)**:
\[
y = \left(\frac{1}{2}\right)^{2-1} - 10 = \frac{1}{2} - 10 = -9.5
\]
Point: \( (2, -9.5) \) (not an integer, skip)
3. **When \( x = 3 \)**:
\[
y = \left(\frac{1}{2}\right)^{3-1} - 10 = \frac{1}{4} - 10 = -9.75
\]
Point: \( (3, -9.75) \) (not an integer, skip)
4. **When \( x = 4 \)**:
\[
y = \left(\frac{1}{2}\right)^{4-1} - 10 = \frac{1}{8} - 10 = -9.875
\]
Point: \( (4, -9.875) \) (not an integer, skip)
5. **When \( x = 5 \)**:
\[
y = \left(\frac{1}{2}\right)^{5-1} - 10 = \frac{1}{16} - 10 = -9.9375
\]
Point: \( (5, -9.9375) \) (not an integer, skip)
6. **When \( x = 6 \)**:
\[
y = \left(\frac{1}{2}\right)^{6-1} - 10 = \frac{1}{32} - 10 \approx -9.96875
\]
Point: \( (6, -9.96875) \) (not an integer, skip)
7. **When \( x = 7 \)**:
\[
y = \left(\frac{1}{2}\right)^{7-1} - 10 = \frac{1}{64} - 10 \approx -9.984375
\]
Point: \( (7, -9.984375) \) (not an integer, skip)
We can make calculations for negative \( x \) values:
1. **When \( x = 0 \)**:
\[
y = \left(\frac{1}{2}\right)^{0-1} - 10 = \frac{1}{0.5} - 10 = 2 - 10 = -8
\]
Point: \( (0, -8) \)
2. **When \( x = -1 \)**:
\[
y = \left(\frac{1}{2}\right)^{-1-1} - 10 = \left(\frac{1}{2}\right)^{-2} - 10 = 4 - 10 = -6
\]
Point: \( (-1, -6) \)
3. **When \( x = -2 \)**:
\[
y = \left(\frac{1}{2}\right)^{-2-1} - 10 = \left(\frac{1}{2}\right)^{-3} - 10 = 8 - 10 = -2
\]
Point: \( (-2, -2) \)
4. **When \( x = -3 \)**:
\[
y = \left(\frac{1}{2}\right)^{-3-1} - 10 = \left(\frac{1}{2}\right)^{-4} - 10 = 16 - 10 = 6
\]
Point: \( (-3, 6) \)
5. **When \( x = -4 \)**:
\[
y = \left(\frac{1}{2}\right)^{-4-1} - 10 = \left(\frac{1}{2}\right)^{-5} - 10 = 32 - 10 = 22
\]
Point: \( (-4, 22) \)
### Summary of Points
Here are the points with integer coordinates we found:
1. \( (0, -8) \)
2. \( (-1, -6) \)
3. \( (-2, -2) \)
4. \( (-3, 6) \)
5. \( (-4, 22) \)
### Final Result
The equation of the horizontal asymptote is:
\[
y = -10
\]
The points to plot on the graph of the function \( y = \left(\frac{1}{2}\right)^{x-1} - 10 \) are:
1. \( (0, -8) \)
2. \( (-1, -6) \)
3. \( (-2, -2) \)
4. \( (-3, 6) \)
5. \( (-4, 22) \)
You can graph the function based on these points and observe the horizontal asymptote at \( y = -10 \).
### Step 1: Find the equation of the asymptote
The function is an exponential decay function, which typically has a horizontal asymptote. As \( x \) approaches infinity, \( \left(\frac{1}{2}\right)^{x-1} \) approaches 0, so we can see if there's a vertical shift affecting the asymptote.
Thus, let's find the horizontal asymptote:
\[
\lim_{{x \to \infty}} \left(\frac{1}{2}\right)^{x-1} - 10 = 0 - 10 = -10
\]
The equation of the horizontal asymptote is:
\[
y = -10
\]
### Step 2: Plot at least five points with integer coordinates
We can calculate the function values for integer values of \( x \).
1. **When \( x = 1 \)**:
\[
y = \left(\frac{1}{2}\right)^{1-1} - 10 = 1 - 10 = -9
\]
Point: \( (1, -9) \)
2. **When \( x = 2 \)**:
\[
y = \left(\frac{1}{2}\right)^{2-1} - 10 = \frac{1}{2} - 10 = -9.5
\]
Point: \( (2, -9.5) \) (not an integer, skip)
3. **When \( x = 3 \)**:
\[
y = \left(\frac{1}{2}\right)^{3-1} - 10 = \frac{1}{4} - 10 = -9.75
\]
Point: \( (3, -9.75) \) (not an integer, skip)
4. **When \( x = 4 \)**:
\[
y = \left(\frac{1}{2}\right)^{4-1} - 10 = \frac{1}{8} - 10 = -9.875
\]
Point: \( (4, -9.875) \) (not an integer, skip)
5. **When \( x = 5 \)**:
\[
y = \left(\frac{1}{2}\right)^{5-1} - 10 = \frac{1}{16} - 10 = -9.9375
\]
Point: \( (5, -9.9375) \) (not an integer, skip)
6. **When \( x = 6 \)**:
\[
y = \left(\frac{1}{2}\right)^{6-1} - 10 = \frac{1}{32} - 10 \approx -9.96875
\]
Point: \( (6, -9.96875) \) (not an integer, skip)
7. **When \( x = 7 \)**:
\[
y = \left(\frac{1}{2}\right)^{7-1} - 10 = \frac{1}{64} - 10 \approx -9.984375
\]
Point: \( (7, -9.984375) \) (not an integer, skip)
We can make calculations for negative \( x \) values:
1. **When \( x = 0 \)**:
\[
y = \left(\frac{1}{2}\right)^{0-1} - 10 = \frac{1}{0.5} - 10 = 2 - 10 = -8
\]
Point: \( (0, -8) \)
2. **When \( x = -1 \)**:
\[
y = \left(\frac{1}{2}\right)^{-1-1} - 10 = \left(\frac{1}{2}\right)^{-2} - 10 = 4 - 10 = -6
\]
Point: \( (-1, -6) \)
3. **When \( x = -2 \)**:
\[
y = \left(\frac{1}{2}\right)^{-2-1} - 10 = \left(\frac{1}{2}\right)^{-3} - 10 = 8 - 10 = -2
\]
Point: \( (-2, -2) \)
4. **When \( x = -3 \)**:
\[
y = \left(\frac{1}{2}\right)^{-3-1} - 10 = \left(\frac{1}{2}\right)^{-4} - 10 = 16 - 10 = 6
\]
Point: \( (-3, 6) \)
5. **When \( x = -4 \)**:
\[
y = \left(\frac{1}{2}\right)^{-4-1} - 10 = \left(\frac{1}{2}\right)^{-5} - 10 = 32 - 10 = 22
\]
Point: \( (-4, 22) \)
### Summary of Points
Here are the points with integer coordinates we found:
1. \( (0, -8) \)
2. \( (-1, -6) \)
3. \( (-2, -2) \)
4. \( (-3, 6) \)
5. \( (-4, 22) \)
### Final Result
The equation of the horizontal asymptote is:
\[
y = -10
\]
The points to plot on the graph of the function \( y = \left(\frac{1}{2}\right)^{x-1} - 10 \) are:
1. \( (0, -8) \)
2. \( (-1, -6) \)
3. \( (-2, -2) \)
4. \( (-3, 6) \)
5. \( (-4, 22) \)
You can graph the function based on these points and observe the horizontal asymptote at \( y = -10 \).
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