Question
Which improper fraction is equivalent to 5 3/4 ? Responses 464 46 fourths - no response given 468 46 eighths - no response given 348 34 eighths - no response given 233
Answers
Answered by
GPT-4o mini
To convert the mixed number \( 5 \frac{3}{4} \) into an improper fraction:
1. Multiply the whole number (5) by the denominator of the fraction (4):
\( 5 \times 4 = 20 \).
2. Add the result to the numerator of the fraction (3):
\( 20 + 3 = 23 \).
3. Place this result over the original denominator (4):
\[ 5 \frac{3}{4} = \frac{23}{4} \].
Thus, \( 5 \frac{3}{4} \) is equivalent to \( \frac{23}{4} \).
Looking at the options you provided, none of them seem to present this fraction. If we consider the fractions converted into improper fractions based on the options you've given:
- 46 fourths = \( \frac{46}{4} \) (which simplifies but does not match),
- 46 eighths = \( \frac{46}{8} \) (does not match as well),
- 34 eighths = \( \frac{34}{8} \) (also not a match),
- 233 does not correlate with any fraction discussed.
In conclusion, the correct improper fraction equivalent to \( 5 \frac{3}{4} \) is \( \frac{23}{4} \), which is not listed in your options.
1. Multiply the whole number (5) by the denominator of the fraction (4):
\( 5 \times 4 = 20 \).
2. Add the result to the numerator of the fraction (3):
\( 20 + 3 = 23 \).
3. Place this result over the original denominator (4):
\[ 5 \frac{3}{4} = \frac{23}{4} \].
Thus, \( 5 \frac{3}{4} \) is equivalent to \( \frac{23}{4} \).
Looking at the options you provided, none of them seem to present this fraction. If we consider the fractions converted into improper fractions based on the options you've given:
- 46 fourths = \( \frac{46}{4} \) (which simplifies but does not match),
- 46 eighths = \( \frac{46}{8} \) (does not match as well),
- 34 eighths = \( \frac{34}{8} \) (also not a match),
- 233 does not correlate with any fraction discussed.
In conclusion, the correct improper fraction equivalent to \( 5 \frac{3}{4} \) is \( \frac{23}{4} \), which is not listed in your options.