Asked by Anonymous

If 1.88 g of copper(II) chloride dihydrate is reduced by Mg(s), what is the minimum mass of Mg(s) required for this reduction?


my work

CuMg --> Cu(s) + Mg
molecular weight= 170.482 CuCl2 . 2H2O
1.88/170.482 = 0.01103 mol CuCl2 . 2H2O
=0.01103 mol Mg

0.01103 * 24.31* 100 = 268 mg
is this correct?
Answered by DrBob222
Technically, no. The 0.268 is ok and it is grams. But placing mg outside makes it 0.269 milligrams which is not correct.
Answered by michele
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