To solve the quadratic equation \( x^2 - 22x + 1 = 15 \) by completing the square, we first rewrite the equation:
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Rearrange the equation: \[ x^2 - 22x + 1 - 15 = 0 \] which simplifies to: \[ x^2 - 22x - 14 = 0 \]
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Move the constant to the right side: \[ x^2 - 22x = 14 \]
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Complete the square. To do this, take half of the coefficient of \( x \) (which is -22), square it, and then add it to both sides. Half of -22 is -11, and squaring it gives 121: \[ x^2 - 22x + 121 = 14 + 121 \]
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This simplifies to: \[ (x - 11)^2 = 135 \]
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Take the square root of both sides: \[ x - 11 = \pm \sqrt{135} \]
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Solve for \( x \): \[ x = 11 \pm \sqrt{135} \]
Now, simplify \( \sqrt{135} \):
- \( 135 = 9 \times 15 = 3^2 \times 15 \), thus \( \sqrt{135} = 3\sqrt{15} \).
- Therefore, we find: \[ x = 11 \pm 3\sqrt{15} \]
Thus, the complete solutions are: \[ x = 11 + 3\sqrt{15}, \quad x = 11 - 3\sqrt{15} \]
Among the options provided, the correct response is: x = 11 + 3√15, 11 - 3√15.