Question
If a box can hold 28 1/8 kilograms, how many 1 7/8 kilogram books will it hold? (1 point) Responses 15 books 15 books 35 books 35 books 48 books 48 books 52 books
Answers
GPT-4o mini
To determine how many \(1 \frac{7}{8}\) kilogram books can fit in a box that holds \(28 \frac{1}{8}\) kilograms, we will first convert both mixed numbers into improper fractions.
1. **Convert \(28 \frac{1}{8}\) to an improper fraction:**
\[
28 \frac{1}{8} = \frac{28 \times 8 + 1}{8} = \frac{224 + 1}{8} = \frac{225}{8}
\]
2. **Convert \(1 \frac{7}{8}\) to an improper fraction:**
\[
1 \frac{7}{8} = \frac{1 \times 8 + 7}{8} = \frac{8 + 7}{8} = \frac{15}{8}
\]
3. **Now, divide the total weight the box can hold by the weight of one book:**
\[
\text{Number of books} = \frac{28 \frac{1}{8}}{1 \frac{7}{8}} = \frac{\frac{225}{8}}{\frac{15}{8}} = \frac{225}{8} \times \frac{8}{15} = \frac{225}{15} = 15
\]
Thus, the box can hold **15 books**.
1. **Convert \(28 \frac{1}{8}\) to an improper fraction:**
\[
28 \frac{1}{8} = \frac{28 \times 8 + 1}{8} = \frac{224 + 1}{8} = \frac{225}{8}
\]
2. **Convert \(1 \frac{7}{8}\) to an improper fraction:**
\[
1 \frac{7}{8} = \frac{1 \times 8 + 7}{8} = \frac{8 + 7}{8} = \frac{15}{8}
\]
3. **Now, divide the total weight the box can hold by the weight of one book:**
\[
\text{Number of books} = \frac{28 \frac{1}{8}}{1 \frac{7}{8}} = \frac{\frac{225}{8}}{\frac{15}{8}} = \frac{225}{8} \times \frac{8}{15} = \frac{225}{15} = 15
\]
Thus, the box can hold **15 books**.