Asked by Anna
An element crystallizes in a body-centered cubic lattice. The edge of the unit cell is 3.5 Angstrom, and the density of the crystal is 7.39g/cm^3. Calculate the atomic weight of the element. A= ? g/mol
Answers
Answered by
Anna
95.4g/mol
Answered by
DrBob222
The bcc has two atoms/unit cell.
The edge is 3.5 x 10^-8 cm = a
Volume = a<sup>3</sup> = 3.5 x 10^-8)^3 cc
mass = volume x density
mass = a<sup>3</sup> x 7.49 g/cc = xx
2atoms/unit cell x atomic mass/6.022 x 10^23 = xx mass
Solve for atomic mass.
The edge is 3.5 x 10^-8 cm = a
Volume = a<sup>3</sup> = 3.5 x 10^-8)^3 cc
mass = volume x density
mass = a<sup>3</sup> x 7.49 g/cc = xx
2atoms/unit cell x atomic mass/6.022 x 10^23 = xx mass
Solve for atomic mass.
Answered by
DrBob222
I made a typo. The density is 7.39, not 7.49 g/cc.
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