Asked by Nikki
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Aluminum nitrite & ammonium chloride react to form aluminum chloride, nitrogen gas and water. What amount of aluminum chloride is present after 43g of ammonium chloride have reacted completely?
I
[Show all work]
Aluminum nitrite & ammonium chloride react to form aluminum chloride, nitrogen gas and water. What amount of aluminum chloride is present after 43g of ammonium chloride have reacted completely?
I
Answers
Answered by
DrBob222
1. Write the balanced chemical equation.
2. Convert 43 g NH4Cl to moles. moles = grams/molar mass.
3. Using the coefficients in the balanced equation, convert moles NH4Cl to moles AlCl3.
4. Now convert moles AlCl3 to grams. g = moles x molar mass.
2. Convert 43 g NH4Cl to moles. moles = grams/molar mass.
3. Using the coefficients in the balanced equation, convert moles NH4Cl to moles AlCl3.
4. Now convert moles AlCl3 to grams. g = moles x molar mass.
Answered by
antonio
Aluminum nitrite and ammonium chloride react to form aluminum chloride, nitrogen, and water. What mass of each substance is present after 62.3 g aluminum nitrite and 51.2 g ammonium chloride react completely?
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