Figure the stored energy at the beginning (compressed 18 cm).
Figure the friction energy it loses as it slides x+18 cm (mg*mu*(x+.18)
final stored energy= 1/2 k x^2 solve for x.
base equation: final stored energy= initial stored energy + friction energy lost.
A 280 g wood block is firmly attached to a very light horizontal spring, as shown in the figure . The block can slide along a table where the coefficient of friction is 0.30. A force of 22 N compresses the spring 18 cm. If the spring is released from this position, how far beyond its equilibrium position will it stretch at its first maximum extension?
3 answers
30
it must be = 0.17
2 answers