Asked by peyton
A 280 g wood block is firmly attached to a very light horizontal spring, as shown in the figure . The block can slide along a table where the coefficient of friction is 0.30. A force of 22 N compresses the spring 18 cm. If the spring is released from this position, how far beyond its equilibrium position will it stretch at its first maximum extension?
Answers
Answered by
bobpursley
Figure the stored energy at the beginning (compressed 18 cm).
Figure the friction energy it loses as it slides x+18 cm (mg*mu*(x+.18)
final stored energy= 1/2 k x^2 solve for x.
base equation: final stored energy= initial stored energy + friction energy lost.
Figure the friction energy it loses as it slides x+18 cm (mg*mu*(x+.18)
final stored energy= 1/2 k x^2 solve for x.
base equation: final stored energy= initial stored energy + friction energy lost.
Answered by
Anonymous
30
Answered by
kuwaiteiiah
it must be = 0.17
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