Use the "backdoor" approach,
that is
find the number of ways when they are together.
then we have EEEE, I, N,N,N,D,D,P,C
arrange 9 things, with 3N's and 2 D's
= 9!/(3!2!)
= 30240
number of arrangements without restriction
= 12!/(4!3!2!) = 1663200
so number of ways when they are not together
= 1663200 - 30240 = 1632960
Find the number of words formed by permuting all the letters
of the word INDEPENDENCE such that the E's do not come together.
2 answers
great answers