Asked by dani
Not sure where to go next. I need to solve this quadratic equation 7x^2-5=0.
This is what I have so far, not sure where/what to do next
x=2/7
x=sqrt2/7 or x=-sqrt2/7* =+/-sqrt2/7
+/-sqrt14/7
not even sure if this is right.
This is what I have so far, not sure where/what to do next
x=2/7
x=sqrt2/7 or x=-sqrt2/7* =+/-sqrt2/7
+/-sqrt14/7
not even sure if this is right.
Answers
Answered by
Reiny
7x^2 - 5 = 0
7x^2 = 5
x^2 = 5/7
x = ± √5/√7
or
x = ± √35/7
7x^2 = 5
x^2 = 5/7
x = ± √5/√7
or
x = ± √35/7
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