Use the table to answer the question.

x 0 2π




y 0 1 0 −1
0
Write the equation of the periodic function represented in the table.

(1 point)
f(x)=sin

1 answer

To determine the periodic function represented in the table, we will first analyze the values provided.

From the table, we can observe the following:

  • When \( x = 0 \), \( y = 0 \)
  • When \( x = 2\pi \), \( y = 1 \)
  • When \( x = 4\pi \), \( y = 0 \)
  • When \( x = 6\pi \), \( y = -1 \)
  • When \( x = 8\pi \), \( y = 0 \)

This pattern suggests that the function is sinusoidal, as we see oscillation through the values \( 0 \), \( 1 \), \( 0 \), \( -1 \), and back to \( 0 \).

The points indicate that:

  • The function has a maximum value of \( 1 \) at \( x = 2\pi \).
  • The function returns to the same maximum every \( 4\pi \) (from \( 0 \to 2\pi \to 4\pi \)).
  • The period of the function is \( 4\pi \).

Since the sine function typically has a period of \( 2\pi \), we can adjust it to have a period of \( 4\pi \) by using the formula \( f(x) = \sin\left(\frac{x}{2}\right) \), which gives it a period of \( 4\pi \).

Thus, the equation of the periodic function represented in the table is:

\[ f(x) = \sin\left(\frac{x}{2}\right) \]

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